Question -
Calculate entropy change for vaporization of 1 mole of liquid water to steam at 100∘C if ΔHv=40.8 kJ mol−1.
Options:
A .  ΔSv=107.38 JK−1 mol−1
B .  ΔSv=109.48 JK−1 mol−1
C .  ΔSv=109.38 JK−1 mol−1
D .  ΔSv=107.38 JK−1 mol−1
Answer: Option C : C For entropy change of vaporization can be given as, ΔSv=ΔHvT Given values are, ΔHv=40.8×103Jmol−1; T=373K Therefore ΔSv=(40.8×103373) ΔSv=109.38JK−1mol−1
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