Question -
1 mole of an ideal gas is compressed isothermally and reversibly at 298 K from a pressure of 1 Pa. To do a work of 100J, to what final pressure should we compress it? (R = 8.314 J/K/mol)
Options:
A .  0.96 Pa
B .  1.0412 Pa
C .  10 Pa
D .  96 Pa
Answer: Option B : B W=−2.303nRTlogP1P2∴logP1P2=W−2.303nRT=100−2.303×1×8.314×298=−0.01753i.e.,logP1−logP2=−0.01753(TheunitsinwhichP1andP2areexpressedmustbeidentical)∴−logP2=−0.01753−logP1∴−logP2=−0.01753+logP1=0.01753+log1=0.01753+0logP2=0.01753⇒P2=Antilog(0.01753)⇒P2=1.0412Pa(SinceunitofP1isPa)
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