Question -
If the r.m.s. velocity of a gas at a given temperature (Kelvin scale) is 300 m/s, whathat will be the r.m.s. velocity of a gas having twice the molecular weight and half the temperature on Kelvin scale =
Options:
A .  300 m/sec
B .  600 m/sec
C .  75 m/sec
D .  150 m/sec
Answer: Option D : D vmax = √3RTM⇒Vmax∞√TM v2v1 = √M1M2×T2T1√12×12⇒v2=v12=3002=150m/sec
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