Question -
A string of length L is fixed at one end and carries a mass M at the other end. The string makes 2Ï€ revolutions per second around the vertical axis through the fixed end as shown in the figure, then tension in the string isÂ
Options:
A .  MLÂ Â Â
B .  2Â ML
C .  4Â ML
D .  16Â ML
Answer: Option D : D T sin θ = M ω2 R T sin θ = M ω2 L sin θ From (i) and (ii) T = M ω2 L = M 4π2n2L = M 4 π2(2π2)L = 16 ML
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