Question -
Figure shows a network of resistances connected to a 2 V battery. If the internal resistance of the battery is negligible current I in the circuit is Â
Options:
A .  0.25 A
B .  0.5 A
C .  0.75 A
D .  1 A
Answer: Option B : B Because PQ=RS the circuit is balanced Wheatstone's bride.Therefore potential at B =potential at D. Hence no current flows through the 5 ohm resistor. It is therefore not effectiveThe equivalent resistance between A and C is the resistance of a parallel combination of P + R = 2 + 4 = 6ohm and Q + S = 4 + 8 = 12ohm which is given by 1R+16+112 R = 4ohm Therefore current l is l=24=0.5 A
Submit Your Solution hear: