Question -
An infinitely long straight conductor is bent into the shape as shown in the figure. It carries a current of i ampere and the radius of the circular loop is r metre. Then the magnetic induction at its centre will be
Options:
A .  μ04π2ir(π+1)
B .  μ04π.2ir(π−1)
C .  Zero
D .  Infinite
Answer: Option B : B The given shape is equivalent to the following diagram The field at o due to straight part of conductor is B1=μ04π.2ir⊙. The field at o due to circular coil isB2=μ04π.2πir⊗. Both fields will act in the opposite direction, hence the total field at O. i.e. B=B2−B1=(μ04π)×(π−1)2ir=μ04π.2ir(π−1)
Submit Your Solution hear: