Question -
 A  100 W bulb B1 and two 60 W bulbs B2 and B3 are connected to a 250 V source as shown in figure. W1, W2and W3are the output powers of the bulbs B1, B2 and B3 respectively thenÂ
Options:
A .  W1>Â W2Â =Â W3
B .  W1>Â W2>Â W3
C .  W1
D .  W1
Answer: Option D : D The resistances of bulbs B1,B2 and B3 respectively are R1v2w1=(250)2100=625 ohm R2=(250)260=1042 ohm =R3 Voltage across B3 is V3=250V Voltage across B1 is V1=VR1(R1+R2)=250×625(625+1042)=93.7V Voltage across B2 is V2=250−93.7=156.3V Power output W1=V2R1=(93.7)2625=14W W2=(156.3)21042=23w W3=(250)21042=60w Hence W1<W2<W3
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