Question -
In the given circuit with steady current the potential drop across the capacitor must be
Options:
A .  V
B .  V2
C .  V3
D .  2V3
Answer: Option C : C In the steady state no current flows in the branch containing the capacitor .Thus the current say l flows in the branches containing R and 2R. Applying Kirchoff's second rule to the loop abcdefa 2V-I(2R)-IR-V=0 l=V3R Potential drop across capacitor =2V-V-l(2R)=V−v3R×2R =V−2v3=v3
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