Projectile Motion(11th And 12th > Physics ) Questions and Answers
Explanation:-
Answer: Option C. -> u sin θ:
C
Since horizontal component of velocity remain always constant therefore only vertical component of velocity changes.
Initially vertical component u sin θ
Finally it becomes zero. So change in velocity =u sin θ
Explanation:-
Answer: Option B. -> 49.0 N–s:
B
Change in momentum between complete projectile motion = 2mu sinθ=2×0.5×98×sin 30∘=49 N−s
Explanation:-
Answer: Option D. -> 1 kg m sec−1:
D
Horizontal momentum remains always constant. So change in vertical momentum (Δ →p) = Final vertical momentum – Initial vertical momentum =−mu sin θ
|ΔP|=0.1×20×sin 30∘=1 kg m/sec
Explanation:-
Answer: Option B. -> mv3(4√2g):
B
L=m u3 cosθ sin2 θ2g=mv3(4√2g) [As θ=45∘]
Explanation:-
Answer: Option A. -> P:
A
Range of projectile will be minimum for that angle which is farthest from 45∘.