P Block Elements(11th And 12th > Chemistry ) Questions and Answers
Question 1.
Ca2B6O11+Na2CO3Fused−−−→(A)+(B)+CaCO3(A)+CO2→(B)+Na2CO3Solution(B)+Conc.HCI→NaCI+Acid↓H2O(C)Strongly−−−−−→heated(D)Acid(C)(D)+CuSO4Heated−−−−−→inflameBlue coloured(E)compoundcompound (E) is -
Cu2O
CuS
CuSO3
Cu(BO2)2
Explanation:-
Answer: Option D. -> Cu(BO2)2 : D
Compound (A) is - NaBO2 Compound (B) is - Na2B4O7 Compound (C) is - H3BO3 Compound (D) is - B2O3 Compound (E) is - Cu(BO2)2
Question 2.
....... is the by-product obtained in the Serpeck's process -
Aqueous solution of borax reacts with two mol of acids. This is because of -
Formation of 2 mol of B(OH)3 only
Formation of 1mol of [B(OH)4]− only
Formation of 1 mol each of B(OH)3 and [B(OH)4]−
Formation of 2 mol each of [B(OH)4]− and B(OH)3, of which only[B(OH)4]− reacts with acid
Explanation:-
Answer: Option D. -> Formation of 2 mol each of [B(OH)4]− and B(OH)3, of which only[B(OH)4]− reacts with acid : D
Na2B4O7+7H2O→2B(OH)3+2Na[B(OH)4]
B(OH)3orH3BO3 is an acid and does not react with acid.
Hence Na[B(OH)4] reacts with acid.
Question 4.
The main factor responsible for weak acidic nature of B-F bonds in BF3 is -
Large electronegativity of F
Three centred two electron bonds in BF3
pp- dp back bonding
pp- pp back bonding
Explanation:-
Answer: Option D. -> pp- pp back bonding : D
It is pp- pp bonding involving B and F atom responsible for the acidic nature of boron halides as BF3<BCl3<BBr3< BI3 smaller atom shows more back bonding
Question 5.
In Al2Cl6, which statement is incorrect-
Four Al - Cl bonds are of same length and two of different length
Six Al - Cl bonds are of same length and two of different length
The angle Cl - Al - Cl is 1100 and 930
The angle Al - Cl - Al is 870
Explanation:-
Answer: Option A. -> Four Al - Cl bonds are of same length and two of different length : A
Thallium shows different oxidation states because -
It is a transition metal
Of inert pair effect
Of its amphoteric character
Of its high reactivity
Explanation:-
Answer: Option B. -> Of inert pair effect : B
Inert pair effect is the phenomenon in which outer shell (ns2)electrons penetrate to (n - 1) d electrons and thus becomes closer to nucleus and are more effectively pulled towards nucleus. This results in less availability of ns electrons for bonding. The inert pair effects begins when n = 4 and increases with increasing value of n.
Question 8.
Which species does not exist -
[BF6]3−
[AlF6]3−
[GaF6]3−
[InF6]3−
Explanation:-
Answer: Option A. -> [BF6]3− : A
BF3−6 does not exist because boron does not have vacant d-subshells
Question 9.
Aluminium vessels should not be washed with materials containing washing soda because:
Washing soda is expensive
Washing soda is easily decomposed
Washing soda reacts with aluminium to form soluble aluminate
Washing soda reacts with aluminium to from insoluble aluminium oxide
Explanation:-
Answer: Option C. -> Washing soda reacts with aluminium to form soluble aluminate : C
2NaOH+2Al+2H2O→2NaAlO2+3H2
Question 10.
Al and Ga have nearly the same covalent radii because of:
Greater shielding effect of s-electrons of Ga atoms
Poor shielding effect of s-electrons of Ga atoms
Poor shielding effect of d-electrons of Ga atoms
Greater shielding effect of d-electrons of Ga atoms
Explanation:-
Answer: Option C. -> Poor shielding effect of d-electrons of Ga atoms : C
Due to poor shielding effect of d-electrons, nuclear attraction over valency electrons increases hence atomic size decreases