True Discount(Quantitative Aptitude > Discount ) Questions and Answers
Explanation:-
Answer: Option A. -> Rs.375Answer: (a)Let the cost price of article be x$500 × 90/100 = 120/100 × x$450 = ${6x}/5$$x = {450 × 5}/6$ = Rs.375Using Rule 6,C.P. = ? , M.P. = Rs.500, r = 20%, D = 10%$\text"MP"/\text"CP" = {100 + r}/{100 - D}$$500/\text"CP" = {100 + 20}/{100 - 10}$C.P.= ${500 × 90}/120$ = Rs.375
Explanation:-
Answer: Option B. -> 1,600Answer: (b)Let the marked price be x.$x × 84/100 = {1200 × 112}/100$$x × 84/100 = 112 × 12$$x = {112 × 1200}/84$ = Rs.1600Using Rule 6,C.P. = Rs.1200, r = 12%, D = 16%$\text"MP"/\text"CP" = {100 + r}/{100 - D}$$\text"MP"/1200 = {100 + 12}/{100 - 16}$M.P.= ${112 × 1200}/84$ = Rs.1600
Explanation:-
Answer: Option C. -> 30%Answer: (c)Let the marked price be Rs.100.S.P. = 90% of 100 = Rs.90Profit = 17%C.P. = Rs.$90 × 100/117$ = Rs.$1000/13$If no discount is allowed,S.P. = Rs.100Profit = Rs.$(100 - 1000/13)$ = Rs.$300/13$Profit % = ${300/13}/{1000/13}$ × 100 = 30%Using Rule 6,Here, D = 10%, r = 17%,Let the M.P. = Rs.100$\text"MP"/\text"CP" = {100 + r}/{100 - D}$$100/\text"CP" = {100 + 17}/{100 - 10}$$100/\text"C.P." = 117/90$C.P. = ${100 × 90}/117 = 1000/13$Profit = S.P. - C.P.= $100 - 1000/13$ = Rs.$300/13$Profit % = ${300/13}/{1000/13} × 100%$ = 30%
Explanation:-
Answer: Option B. -> Rs.32Answer: (b)Marked price = Rs.50S.P. after discount = 80% of 50 = Rs.40If the CP of article be x, then${125 × x}/100 = 40$$x = {40 × 100}/125$ = Rs.32Using Rule 6,Here, M.P. = Rs.50, C.P. = ?,r = 25%, D = 20%$\text"MP"/\text"CP" = {100 + r}/{100 - D}$$50/\text"CP" = {100 + 25}/{100 - 20}$C.P.= ${50 × 80}/125$ = Rs.32
Explanation:-
Answer: Option A. -> Rs.800Answer: (a)Cost price of article = Rs.x$x × 140/100 × 95/100 = 1064$$x = {1064 × 100 × 100}/{140 × 95}$ = Rs.800
Explanation:-
Answer: Option A. -> Rs.680Answer: (a)Using Rule 5,Effective discount= 25 + 15 - ${25 × 15}/100$= 40 - 3.75 = 36.25 %CP for buyer= (100 - 36.25) % of 800= ${63.75 × 800}/100$ = Rs.510To gain 20%,SP = Rs.$({120 × 510}/100)$ = Rs.612Let the list price be Rs.x.90% of x = Rs.612${90x}/100$ = 612$x = 61200/90$ = Rs.680
Explanation:-
Answer: Option A. -> 25%Answer: (a)After a discount of 5%SP = ${95 × 16000}/100$ = Rs.15200Let the second discount be x%.x% of 15200 = (15200 - 11400)${x × 15200}/100 = 3800$$x = {3800 × 100}/15200 = 25$Second discount = 25%Using Rule 3,Here, M.P. = 16000, S.P. = 11400, $D_1 = 5%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$11400 = 16000$({100 - 5}/100)({100 - D_2}/100)$$114000/{16 × 95} = 100 - D_2$$75 = 100 - D_2 ⇒ D_2$ = 25%
Explanation:-
Answer: Option D. -> Loss of Rs.5.76Answer: (d)Using Rule 5,Equivalent discount for two successive discounts of 8% and 8%= $(8 + 8 - {8 × 8}/100)$%= (16–0.64) % = 15.36 %SP = (100 –15.36) % of 900= Rs.$({84.64 × 900}/100)$ = Rs.761.76For a single discount of 16%,SP = 84% of 900= Rs.$({84 × 900}/100)$ = Rs.756Certainly seller will lose in this case.Loss = Rs. (761.76 - 756) = Rs.5.76
Explanation:-
Answer: Option B. -> 13%Answer: (b)Total discount=Rs.(820 - 570.72) = Rs.249.28First discount = $820 × 20/100$ = Rs.164Second discount= Rs.(249.28 - 164) = Rs.85.28Price of the article after first discount= Rs.(820 - 164) = Rs.656If the second discount be x% , thenx% of 656 = 85.28$x = {85.28 × 100}/656 = 13%$Using Rule 3,Here, M.P. = Rs.820, S.P. = 570.72, $D_1 = 20%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$$570.72 = 820 ({100 - 20}/100)({100 - D_2}/100)$$5707200/{820 × 80} = 100 - D_2$$100 - D_2 = 87 ⇒ D_2$ = 13%
Explanation:-
Answer: Option A. -> 15 per centAnswer: (a) Let the second discount be x per cent.According to the question,$450 × {100 - 10}/100 × {100 - x}/100$ = 344.25100 - x = ${344.25 × 100 × 100}/{450 × 90}$100 - x = 85x = 100 - 85 = 15%.Using Rule 3,Here, M.P. = Rs.450, S.P. = Rs.344.25, $D_1 = 10%, D_2$ = ?S.P. = M.P.$({100 - D_1}/100)({100 - D_2}/100)$$344.25 = 450 × ({100 - 10}/100)({100 - D_2}/100)$$3442500/{450 × 90} = (100 - D_2)$$85 = 100 - D_2 ⇒ D_2$ = 15%