Internetworking(Networking ) Questions and Answers

Question 1. Which layer 1 devices can be used to enlarge the area covered by a single LAN segment?
1. Switch
2. NIC
3. Hub
4. Repeater
5. RJ45 transceiver
  1.    1 only
  2.    1 and 3
  3.    3 and 4
  4.    5 only
  5.    All of the above
Explanation:-
Answer: Option C. -> 3 and 4
Not that you really want to enlarge a single collision domain, but a hub (multiport repeater) will provide this for you.

Question 2. Which of the following describe router functions?
  1.    Packet switching
  2.    Packet filtering
  3.    Internetwork communication
  4.    Path selection
  5.    All of the above
Explanation:-
Answer: Option E. -> All of the above
Routers provide packet switching, packet filtering, internetwork communication, and path selection.

Question 3. A receiving host has failed to receive all of the segments that it should acknowledge. What can the host do to improve the reliability of this communication session?
  1.    Send a different source port number.
  2.    Restart the virtual circuit.
  3.    Decrease the sequence number.
  4.    Decrease the window size.
Explanation:-
Answer: Option D. -> Decrease the window size.
A receiving host can control the transmitter by using flow control (TCP uses Windowing by default). By decreasing the window size, the receiving host can slow down the transmitting host so the receiving host does not overflow its buffers.

Question 4. Routers operate at layer _____. LAN switches operate at layer _____. Ethernet hubs operate at layer _____. Word processing operates at layer _____.
  1.    3, 3, 1, 7
  2.    3, 2, 1, none
  3.    3, 2, 1, 7
  4.    3, 3, 2, none
  5.    All of the above
Explanation:-
Answer: Option B. -> 3, 2, 1, none
Routers operate at layer 3. LAN switches operate at layer 2. Ethernet hubs operate at layer 1. Word processing applications communicate to the Application layer interface, but do not operate at layer 7, so the answer would be none.

Question 5. Why does the data communication industry use the layered OSI reference model?
1. It divides the network communication process into smaller and simpler components, thus aiding component development, design, and troubleshooting.
2. It enables equipment from different vendors to use the same electronic components, thus saving research and development funds.
3. It supports the evolution of multiple competing standards and thus provides business opportunities for equipment manufacturers.
4. It encourages industry standardization by defining what functions occur at each layer of the model.
  1.    1 only
  2.    1 and 4
  3.    2 and 3
  4.    3 only
Explanation:-
Answer: Option B. -> 1 and 4
The main advantage of a layered model is that it can allow application developers to change aspects of a program in just one layer of the layer model's specifications.
Advantages of using the OSI layered model include, but are not limited to, the following:
It divides the network communication process into smaller and simpler components, thus aiding compo-nent development, design, and troubleshooting;
it allows multiple-vendor development through standardization of network components;
it encourages industry standardization by defining what functions occur at each layer of the model;
it allows various types of network hardware and software to communicate;
and it prevents changes in one layer from affecting other layers, so it does not hamper development.

Question 6. What are the decimal and hexadecimal equivalents for the binary number 10110111?
  1.    69/0x2102
  2.    183/B7
  3.    173/A6
  4.    83/0xC5
Explanation:-
Answer: Option B. -> 183/B7
You must be able to take a binary number and convert it into both decimal and hexadecimal.
To convert to decimal, just add up the 1s using their values. The values that are turned on with the binary number of 10110111 are 128 + 32 + 16 + 4 + 2 + 1 = 183.
To get the hexadecimal equivalent, you need to break the eight binary digits into nibbles (4 bits), 1011 and 0111.
By add-ing up these values, you get 11 and 7. In hexadecimal, 11 is B,
so the answer is 0xB7.

Question 7. Which three statements are true about the operation of a full-duplex Ethernet network?
1. There are no collisions in full-duplex mode.
2. A dedicated switch port is required for each full-duplex node.
3. Ethernet hub ports are preconfigured for full-duplex mode.
4. In a full-duplex environment, the host network card must check for the availability of the network media before transmitting.
5. The host network card and the switch port must be capable of operating in full-duplex mode.
  1.    1, 2, and 5
  2.    2 and 4
  3.    2, 3 and 4
  4.    5 only
Explanation:-
Answer: Option A. -> 1, 2, and 5
Full-duplex means you are using both wire pairs simultaneously to send and receive data. You must have a dedicated switch port for each node, which means you will not have collisions. Both the host network card and the switch port must be capable and set to work in full-duplex mode.

Question 8. Which of the following are types of flow control?
1. Buffering
2. Cut-through
3. Windowing
4. Congestion avoidance
  1.    1 and 2
  2.    1, 3 and 4
  3.    2 only
  4.    3 only
Explanation:-
Answer: Option B. -> 1, 3 and 4
The common types of flow control are buffering, windowing, and congestion avoidance.

Question 9. What is the purpose of flow control?
  1.    To ensure that data is retransmitted if an acknowledgment is not received.
  2.    To reassemble segments in the correct order at the destination device.
  3.    To provide a means for the receiver to govern the amount of data sent by the sender.
  4.    To regulate the size of each segment.
Explanation:-
Answer: Option C. -> To provide a means for the receiver to govern the amount of data sent by the sender.
Flow control allows the receiving device to control the transmitter so the receiving device's buffer does not overflow.

Question 10. What are two purposes for segmentation with a bridge?
1. To add more broadcast domains.
2. To create more collision domains.
3. To add more bandwidth for users.
4. To allow more broadcasts for users.
  1.    1 only
  2.    2 and 3
  3.    2 and 4
  4.    4 only
Explanation:-
Answer: Option B. -> 2 and 3
Bridges break up collision domains, which allow more bandwidth for users.