Genomic And Screening Libraries(Engineering > Genetic Engineering ) Questions and Answers

Question 1. What is the second primer in the case of 5’ RACE?
  1.    Internal primer
  2.    Oligo-dA sequence
  3.    Adaptor-oligo-dT primer
  4.    Oligo-dT adaptor molecule
Explanation:-
Answer: Option C. -> Adaptor-oligo-dT primer
Answer: (c).Adaptor-oligo-dT primer
Question 2. Choose the correct statement for modification of homopolymer tailing method.
  1.    It includes modification of primers
  2.    Primers are varied by simply altering their size by randomly adding or removing bases
  3.    The 5’ end of the first cDNA strand is tailed with C residues
  4.    A single stranded oilgonucleotide is then used for second strand synthesis
Explanation:-
Answer: Option A. -> It includes modification of primers
Answer: (a).It includes modification of primers
Question 3. By synthesizing two strands separately then annealing them leads to formation of double stranded oligonucleotide.
  1.    True
  2.    False
  3.    May be True or False
  4.    Can't say
Explanation:-
Answer: Option A. -> True
Answer: (a).True
Question 4. RNaseH method and homopolymer tailing method generates blunt ended cDNA molecules. Which of the following can be used for attaching them to vector?
  1.    Blunt ended ligation
  2.    Addition of linkers
  3.    Using appropriate restriction enzymes
  4.    All the methods can be used equivalently
Explanation:-
Answer: Option D. -> All the methods can be used equivalently
Answer: (d).All the methods can be used equivalently
Question 5. Sometimes the required mRNA is present in less number. So the process of increasing the representation of rare mRNAs is called as ____________
  1.    amplification
  2.    normalization
  3.    selection
  4.    narrowing
Explanation:-
Answer: Option B. -> normalization
Answer: (b).normalization
Question 6. Choose the correct statement in order to enrich rare species.
  1.    The most basic principle relies on the kinetics of hybridization
  2.    A collection of single stranded molecules is allowed to reanneal under given conditions
  3.    The strands which are less abundant are able to find their complement easily
  4.    The left over molecules are more abundant in nature
Explanation:-
Answer: Option A. -> The most basic principle relies on the kinetics of hybridization
Answer: (a).The most basic principle relies on the kinetics of hybridization
Question 7. Choose the correct statement for libraries constructed by mixing cell types differing in the sequences they are having.
  1.    The driver and tracer are mixed in double stranded form
  2.    Tracer is in stoichiometric excess in comparison to driver
  3.    Tracer and driver are in the same amount
  4.    The sequences are allowed to hybridize
Explanation:-
Answer: Option D. -> The sequences are allowed to hybridize
Answer: (d).The sequences are allowed to hybridize
Question 8. Which statement holds true for hydroxyapatite?
  1.    It binds to single stranded molecules more tightly than double stranded molecules
  2.    It binds to linear molecules more tightly than circular molecules
  3.    It binds to circular molecules more tightly than linear molecules
  4.    It binds to double stranded molecules more tightly than single stranded molecules
Explanation:-
Answer: Option D. -> It binds to double stranded molecules more tightly than single stranded molecules
Answer: (d).It binds to double stranded molecules more tightly than single stranded molecules
Question 9. Libraries in which a particular sequence is present in one organism but are absent from another organism, are called as ___________
  1.    normalized libraries
  2.    subtractive libraries
  3.    selective libraries
  4.    partial libraries
Explanation:-
Answer: Option B. -> subtractive libraries
Answer: (b).subtractive libraries
Question 10. The nucleic acid from the cell type that contains the sequence we are interested in is called ___________
  1.    driver
  2.    subtractive sequence
  3.    tracer
  4.    wanted sequence
Explanation:-
Answer: Option C. -> tracer
Answer: (c).tracer
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