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Site Investigation And Soil Sampling(Engineering > Foundation Engineering ) Questions and Answers
Home
Topic
Engineering
Foundation Engineering
Site Investigation And Soil Sampling
Question 1.
The standard penetration test is performed in clear hole of _____________ mm in diameter.
10 to 30
30 to 50
55 to 150
150 to 1000
Explanation:-
Answer: Option C. ->
55 to 150
Answer:
(c).
55 to 150
Question 2.
The sampler in standard penetration test has outer diameter of _________ mm.
50.8
60.3
70.3
80.2
Explanation:-
Answer: Option A. ->
50.8
Answer:
(a).
50.8
Question 3.
The sample in standard penetration test has inner diameter of _________ mm.
50.8
60
35
75
Explanation:-
Answer: Option C. ->
35
Answer:
(c).
35
Question 4.
The sample is driven by a weight of _____________ in sample in standard penetration test.
65 kg
14 kg
55 kg
100 kg
Explanation:-
Answer: Option A. ->
65 kg
Answer:
(a).
65 kg
Question 5.
The height of the free fall in sample in standard penetration test is ___________
50 cm
75 cm
100 cm
150 cm
Explanation:-
Answer: Option B. ->
75 cm
Answer:
(b).
75 cm
Question 6.
When deeper layers have increasingly greater density, the seismic refraction method is fast.
True
False
May be True or False
Can't say
Explanation:-
Answer: Option A. ->
True
Answer:
(a).
True
Question 7.
If σ’ is the effective overburden pressure, then the effective penetration resistance is given by _____________
Nₑ=\(N \frac{50}{1.42σ^{‘}}\)
Nₑ=\(N \frac{50}{σ^{‘}+10}\)
Nₑ=\(N \frac{1}{1.42σ^{‘}+10}\)
Nₑ=\(N \frac{50}{1.42σ^{‘}+10}\)
Explanation:-
Answer: Option D. ->
Nₑ=\(N \frac{50}{1.42σ^{‘}+10}\)
Answer:
(d).
Nₑ=\(N \frac{50}{1.42σ^{‘}+10}\)
Question 8.
The essential feature of reinforced earth is that __________ develops between compacted layer of earth and reinforcing elements.
friction
tension
compression
shear
Explanation:-
Answer: Option A. ->
friction
Answer:
(a).
friction
Question 9.
The equivalent penetration resistance is given by ___________
Nₑ=15+\(\frac{1}{2}\)(N+15)
Nₑ=\(\frac{1}{2}\)(N-15)
Nₑ=15+\(\frac{1}{2}\)(N-15)
Nₑ=15+\(\frac{1}{2}\)(N)
Explanation:-
Answer: Option C. ->
Nₑ=15+\(\frac{1}{2}\)(N-15)
Answer:
(c).
Nₑ=15+\(\frac{1}{2}\)(N-15)
Question 10.
______ is developed in reinforcement.
Friction
Tension
Compression
Shear
Explanation:-
Answer: Option B. ->
Tension
Answer:
(b).
Tension
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