Subscripting(C++ Programming ) Questions and answers for exam Preparation

Question 1.

What do we need to use when we have multiple subscripts?

operator()
operator[]
operator
None of the mentioned

Explanation:-

Answer: Option A. -> operator()

The reason is that operator[] always takes exactly one parameter, but operator() can take any

number of parameters.

Question 2.

What do we need to do to pointer for overloading the subscript operator?

reference pointer
dereference pointer
store it in heap
None of the mentioned

Explanation:-

Answer: Option B. -> dereference pointer

If you have a pointer to an object of some class type that overloads the subscript operator, you

have to dereference that pointer in order to free the memory.

Question 3.

What is the output of this program?

1.
#include
2.
using namespace std;
3.
class sample
4.
{
5.
private:
6.
int* i;
7.
int j;
8.
public:
9.
sample (int j);
10.
~sample ();
11.
int& operator [] (int n);
12.
};
13.
int& sample::operator [] (int n)
14.
{
15.
return i[n];
16.
}
17.
sample::sample (int j)
18.
{
19.
i = new int [j];
20.
j = j;
21.
}
22.
sample::~sample ()
23.
{
24.
delete [] i;
25.
}
26.
int main ()
27.
{
28.
sample m (5);
29.
m [0] = 25;
30.
m [1] = 20;
31.
m [2] = 15;
32.
m [3] = 10;
33.
m [4] = 5;
34.
for (int n = 0; n 35.
cout

252015105
510152025
51015
None of the mentioned

Explanation:-

Answer: Option A. -> 252015105

In this program, we are printing the array in the reverse order by using subscript operator.
Output:
$ g++ sub4.cpp
$ a.out
252015105

Question 4.

What is the output of this program?

1.
#include
2.
using namespace std;
3.
const int limit = 4;
4.
class safearray
5.
{
6.
private:
7.
int arr[limit];
8.
public:
9.
int& operator [](int n)
10.
{
11.
if (n == limit - 1)
12.
{
13.
int temp;
14.
for (int i = 0; i 15.
{
16.
if (arr[n + 1] > arr[n])
17.
{
18.
temp = arr[n];
19.
arr[n] = arr[n + 1];
20.
arr[n + 1] = temp;
21.
}
22.
}
23.
}
24.
return arr[n];
25.
}
26.
};
27.
int main()
28.
{
29.
safearray sa1;
30.
for(int j = 0; j 31.
sa1[j] = j*10;
32.
for(int j = 0; j 33.
{
34.
int temp = sa1[j];
35.
cout

0102030
1020300
3020100
error

Explanation:-

Answer: Option A. -> 0102030

In this program, we are returning the array element by the multiple of 10.
Output:
$ g++ sub2.cpp
$ a.out
0102030

Question 5.

What is the output of this program?

1.
#include
2.
using namespace std;
3.
class A
4.
{
5.
public:
6.
int x;
7.
A(int n = 0) : x(n) {};
8.
int& operator[](int n)
9.
{
10.
cout

110
111
011
001

Explanation:-

Answer: Option D. -> 001

In this program, we overloading the operator[] by using subscript operator.
Output:
$ g++ sub3.cpp
$ a.out
001

Question 6.

What is the output of this program?

1.
#include
2.
using namespace std;
3.
class numbers
4.
{
5.
private:
6.
int m_nValues[10];
7.
public:
8.
int& operator[] (const int nValue);
9.
};
10.
int& numbers::operator[](const int nValue)
11.
{
12.
return m_nValues[nValue];
13.
}
14.
int main()
15.
{
16.
numbers N;
17.
N[5] = 4;
18.
cout

5
4
3
6

Explanation:-

Answer: Option B. -> 4

In this program, We are getting the values and returning it by overloading the subscript operator.
Output:
$ g++ sub1.cpp
$ a.out
4

Question 7.

Pick out the correct statement.

subscript operator has a higher precedence than the assignment operator.
subscript operator has a lower precedence than the assignment operator.
subscript operator is used with string elements.
None of the mentioned

Explanation:-

Answer: Option A. -> subscript operator has a higher precedence than the assignment operator.

None.

Question 8.

subscript operator is used to access which elements?

string
char
array
all of the mentioned

Explanation:-

Answer: Option C. -> array

None.

Question 9.

How many arguments will the subscript operator will take for overloading?

1
2
0
as many as possible

Explanation:-

Answer: Option A. -> 1

The subscript operator overload takes only one argument,
but it can be of any type.